Using the Cauchy-Riemann conditions, tell if $f(z) = z^{*}$ is analytic
I have tried this:
$Z = x + iy$
$f(x + iy) = Z^{*} = x - iy$
$U(x,y) = x$
$V(x,y) = -y$
$U_x = 1$ Deriving respect to $x$
$V_x = 0$ Deriving respect to $x$
$U_y = 0$ Deriving respect to $y$
$V_y = -1$ Deriving respect to $y$
Then $U_x <> V_y$ and I suppose that $f(z) = z^{*}$ is not analytic. But I'm not sure, I think I'm wrong. Could you help me, please?
We have that $V_y = -1$. Since $U_x \not = V_y$, the Cauchy Riemann equations are not satisfied.