I read on many references that : given $G$ a finite group which has an irreducible faithful representation, then its center $Z(G)$ is cyclic. I want to prove it over $\mathbb{C}$. Any help ?
2026-03-25 07:45:01.1774424701
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Center of an irreducible faithful representation is cyclic.
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The $A$ group of automorphisms of the representation $f:G\rightarrow Gl(V)$ is contained in the group of homothetic map $(h(x)=cx, x\in\mathbb{C})$ since the representation is irreducible (Schur's lemma), you deduce that for every $g\in Z(G)$, $g(x)=c_gx$, $|c_g|=1$ since $G$ is finite. A finite subgroup of $S^1$ is cyclic.
The answer is here : Proof. I will let my post in case of other people ask the question.