My textbook, as an aside, defines the Cesáro sum as follows: $$ \sigma_n= \frac{s_1+...+s_n}{n}= \frac{1}{n}\sum_{k=1}^ns_k, $$ where $$ s_n = \sum_{k=1}^na_k. $$ This method is used, I am told, to find a value of otherwise divergent sums. For exemple the sum $1-1+1-1+1-1+1-1+...$ becomes $1/2$. The notation $(C,2)$ means that you have calculated the Cesáro sum of a Cesáro sum. Let's say you have a sum that doesn't have a finite value until you calculate $(C,10)$, is $(C,10)$ the actual limit?
Is the Cesáro sum the limit of the series or simply a value that coincides with the limit for convergent series?
The limit of a convergent series coincides with its [first] Cesáro sum (proof) and consequently, with its higher order Cesáro sums as well.
In particular, the contrapositive states that if $(C,1)$ does not exist, then the series does not converge.