From Cover and Thomas, Elements of Information Theory:

Why isn't it: $ \log_b(p) = \frac{\log_a(p)}{\log_a(b)} $, so that $ H_a(X) $ is multiplied with $ \frac{1}{\log_b a} $?
From Cover and Thomas, Elements of Information Theory:

Why isn't it: $ \log_b(p) = \frac{\log_a(p)}{\log_a(b)} $, so that $ H_a(X) $ is multiplied with $ \frac{1}{\log_b a} $?
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