We know that, $1^2+2^2+.......+n^2 = n(n+1)(2n+1)/6$
$x=1^2+2^2+.......+8^2$$=8(8+1)(2*8+1)/6$$=204$
So, number of total squares $= 204$
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Bumbble Comm
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There are $8 \times 8=64$ squares of the size $1 \times 1$, $7 \times 7=49$ squares of the size $2 \times 2$, and so on. So the answer is $1^2 + 2^2 + 3^2 + \dots + 8^2$ which equals $204$.
Number of squares $= x$
We know that, $1^2+2^2+.......+n^2 = n(n+1)(2n+1)/6$
$x=1^2+2^2+.......+8^2$ $=8(8+1)(2*8+1)/6$ $=204$
So, number of total squares $= 204$