7 identical apples and 13 identical oranges are to be arranged in a circle so that no two apples are consecutive. No.of ways of doing it is?
I do know about circular permutations and clockwise, anticlockwise arrangements but here the apples and oranges are identical .
Hint:
There must at least be one orange between two apples. As a result, we must use $7$ apples and $7$ oranges (circular permutation).
How many spots are there left for the $6$ remaining oranges? Therefore how many combinations are there?