A small mass is suspended by a light rod from a pivot P. The mass moves with constant speed in a horizontal circle. The rod has length 1 metre and makes an angle of $30^\circ$ with the vertical. Assume $g=9.8ms^{-2}$
I solved part $A$ and $B$ calculating that the mass takes $1.87$seconds to complete one revolution. I also solved that the speed of the mass is about $1.68m/s$
However part $C$ says, if the speed of mass is doubled, show that the rod will make an angle of $54^\circ 44 '$ with the vertical.
THIS means $3.36m/s$. But how would you calculate this. You know equations such as velocity = radius $\times \omega$ . However, radius changes because you are going faster. Angular velocity also changes because you are going faster.
I have also considered speed $= \frac{\text{distance}}{\text{time}}$