In Angelo Margaris's book First Order Mathematical Logic it is written (see below),
Then,
Questions
In the above proof I don't understand what am I supposed to do at the second step. Can anyone explain that to me?
How from "$P$ admits $t$ for $v$" it follows that "$\sim P$ admits $t$ for $v$" (because otherwise you can't use Axiom 5 which says that $\forall v Q\to Q(t/v)$ provides $Q$ admits $t$ for $v$)?


