Classical Rigid body Mechanics

Question

A thin heavy disc can turn freely, about an axis in its own plane, and this revolves horizontally with a uniform angular velocity $\omega$ about a fixed point on itself. Show that the inclination $\theta$ of the plane of the disc to the vertical is $$ \cos^{-1} ( \frac{gh} {k^2 w^2})$$ where h is the distance of the Centre of Inertia of the disc from the axis and k is the radius of gyration of the disc about the axis.