Function $d_0$ is given, $d_{n+1}(y)=d_n'(y)d(y)$ for every $n\in\mathbb{Z}$ (apostrophe means differentiation).
Can we write a closed formula (or at least an explicit sum) for:
$d_n(y)$?
$d_0(y)+d_1(y)t+d_2(y)t^2+\dots+d_n(y)t^n$?
Function $d_0$ is given, $d_{n+1}(y)=d_n'(y)d(y)$ for every $n\in\mathbb{Z}$ (apostrophe means differentiation).
Can we write a closed formula (or at least an explicit sum) for:
$d_n(y)$?
$d_0(y)+d_1(y)t+d_2(y)t^2+\dots+d_n(y)t^n$?
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