Closed linear span of translations of simple step functions

95 Views Asked by At

This paper utilizes Wiener's tauberian theorem to indicate that the closed linear span of translations of any simple step function is equal to $L^p[a,b]$, where $1< p \leq \infty$ and $[a,b]$ are real finite constants.

However, I was under the impression that we could use the simple function approximation lemma to approximate any $L^1[a,b]$ function to arbitrary accuracy using translates of simple step functions.

My logic for this would be that the closed linear span of translates of a simple step function contains all simple functions, which are dense in $L^p[a,b]$ for $1\leq p<\infty$ from the simple function approximation lemma.

What is the error in my logic?

1

There are 1 best solutions below

2
On BEST ANSWER

Why would the closed linear span of the translates of a single simple step function contain all simple functions? This isn't obvious at all. Consider the simple step function $1_{[0,1]}$. How do you write the characteristic function $1_A$ of an arbitrary measurable set $A$ (of finite measure) as a limit of linear combinations of translates of $1_{[0,1]}$?