Cofinality assuming GCH

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There is this statement that GCH holds iff any pair of regular cardinals $\kappa,\lambda$ such that $\kappa<\lambda$ satisfy that $\lambda^\kappa = \lambda$.

Assume we do have two such cardinals. Take the sequence $\langle\lambda^\xi\mid \xi<\kappa\rangle$, then it seems that $\lim_{\xi\to\kappa} \lambda^\xi = \lambda^\kappa = \lambda$ and so $\operatorname{cf}(\lambda) \le \kappa < \lambda$ contradicting regularity.

I am obviously missing something, but I have no idea what, because if my reasoning is correct it seems that under these hypotheses there could not be two different regular cardinals.

Thanks in advance!

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Your mistake is that under the working assumption, $\lambda^\xi=\lambda$. So the sequence is constant. Therefore the cofinality of $\lambda$ is not $\kappa$ or less, because that would require a sequence of cardinals smaller than $\lambda$ itself.