The projective special linear groups $PSL(2,4)$, $PSL(2,5)$ and $PSL(2,9)$ have the property that their orders equal the order of an alternating group. They are also isomorphic to the respective alternating groups.
In this case, we have that $|PSL(2,4)| = |PSL(2,5)| = |A_5|\ $ and $|PSL(2,9)| = |A_6|$. Let $F$ be a finite field. The order of $|PSL(2,F)|$ is given by $(2^n - 1)2^n(2^n + 1)$ when $F$ is of characteristic $2$. Otherwise it is equal to $\frac{1}{2}(p^n - 1)p^n(p^n + 1)$, where $p$ is the characteristic of $F$.
I've been wondering about the following question: when is $|PSL(2,F)| = |A_k|$? In other words, for which $n$ and $k$ the equations
\begin{align*} & 2^{n+1}(2^n - 1)(2^n + 1) = k!\\ &(p^n - 1)p^n(p^n + 1) = k! \text{, where p is an odd prime} \end{align*}
have solutions? Are there only finitely many solutions? And to generalize, what about $PSL(m, F)$?
This is exactly the topic of Artin (1955a). You'll find proofs of Ted's assertions there. Artin (1955b) handles the other simple groups known at the time. Garge (2005) is handy as it also handles semi-simple groups (so in particular, one can mostly identify a chief factor solely by its order, other than the known problem of |Bn|=|Cn| and |A8| = |PSL(3,4)|).