Let's consider the following variant of Collatz (3n+1) :
if $n$ is odd then $n \to 3n+1$
if $n$ is even then you can choose : $n \to n/2$ or $n \to 3n+1$
With this definition, is it possible to construct a cycle other than the trivial one, i.e., $1\to 4 \to 2 \to 1$?
Best regards
$$7\to 22$$ $$22\to11$$ $$11\to34$$ $$34\to17$$ $$17\to52$$ $$52\to26\to13$$ $$13\to40$$ $$40\to20\to10\to5$$ $$5\to16$$ $$16\to8\to4\to2$$ $$2\to 3\cdot2+1=7$$