Friends, for 3 coin flips, the total possible outcomes are 8, given by 2x2x2. But if the order does not matter for me, i should find the combination, which is 4 (TTT, HHH, HHT, HTT).
For 3 coin flips, i can list out the 8 possible outcomes and cross out the repeats to find the number of combination. What if i am to do 10 coin flips? How can i find the number of combination w/o listing all possible outcomes and then crossing out the repeats?
Appreciate your help.
For $10$ coins, there is one configuration with $0$ head, there is one configuration with $1$ head, one configuration with $2$ heads, one configuration with $3$ heads and so on. $\ldots$, one configuration with $10$ heads.
In general, if you have $n$ coins, you have $n+1$ combinations.