In how many ways can 4 women and 3 men be arranged in a circle? In how many ways can this be done if the tallest woman and shortest man must be next to each other? Ans: 240
I did the first question and got 720 (6!), but I do not get the second part.
2026-05-04 18:54:41.1777920881
Combinations and permutations help
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$5!\times 2$=240. You bound the tallest woman and the shortest man together and view them as one person and do permutation. We have $5!$. Since the tallest woman can be the left or the right hand side of the man. So, we have 2 variants for each permutation. Hence, the total number is $5!\times 2$.