I'm working with some result in Do carmo, Riemannian Geometry. Which consits in to find all isometries in $\mathbb{H}^n$, but in the case $\mathbb{H}^n$, $n \geq 3$, the autor said the comformal map $h$ maps $\partial \mathbb{H}^n$ to $\partial \mathbb{H}^n$. In a first place I think that statement was due some special property of comformal maps. But I find this
Does a conformal map take boundaries to boundaries?
So, I don't know how prove this affirmation. Some hint?
Thanks in advance!