commutativity of cycle permutations

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How is the following true, (given two cycle permutations a and b) $(a)^{-1} (b)^{-1} = ((b)(a))^{-1}$ where b and a contain one of the same elements. isn't it only disjoint cycles that are commutative?

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Two things to note:

(1) $a^{-1}b^{-1}=(ba)^{-1}$ is not showing commutativity of two elements. (Commutativity would be $a^{-1}b^{-1}=b^{-1}a^{-1}$.)

(2) Sometimes nondisjoint cycles commute. For instance $(12345)(13524)=(13524)(12345)$