- Is the Lie group generated by this Lie algebra compact or not?
$$ [X_i,X_j]=0, [H_i,H_j]=f^{ijk} X_k, [X_i,H_j]=0 $$
$f^{123}>0$, and $i,j,k \in \{ 1,2,3\}$. There are 6 generators in total for the Lie algebra.
- What is the easy way to check the compactness of this Lie group? Is the Lie group unique or not? If there is a unique simply connected Lie group associated to a (finite-dimensional) Lie algebra, then whether the compactness of this simply connected Lie group unique determined?
Any constructive comment or answer will be helpful.
I suppose the invariant bilinear matrix replacing the degenerate Killing form for this Lie algebra case is:
$$ \begin{pmatrix} 0 & 0& 0 & 1 & 0& 0\\ 0 & 0& 0 & 0 & 1& 0\\ 0 & 0& 0 & 0 & 0& 1\\ 1 & 0& 0 & 0 & 0& 0\\ 0 & 1& 0 & 0 & 0& 0\\ 0 & 0& 1 & 0 & 0& 0 \end{pmatrix} $$ where the 1, 2, 3, 4, 5,6 components correspond to $X1,X2,X3,H1,H2,H3$ respectively.
So the invariant bilinear matrix is not positive definite, its eigenvalues are 1,1,1,-1,-1,-1,; so the corresponding Lie group will be non-compact.