comparing area of a square with area of rectangle

Question

If we have a geometric sequence we have $a_1, a_1*r, a_2*r$

So $b=a_1*r$ and $c=a_2*r$

The square has area $b^2$ which is $(a_1*r)^2$ and the rectangle has area $ac = a_1*a_2*r$

I don't know which one is bigger or if this was even a correct way of interpreting the problem. Can someone please help.

Answer 1

$a$, $b$ and $c$ is in a geometric sequence.

$\dfrac{b}{a}=\dfrac{c}{b}$

So, $ac=b^2$.