Comparison of the gradients of two harmonic functions near the boundary

165 Views Asked by At

Let $\Omega$ an open bounded domain in $R^n$. Let $u,v$ be nonconstant smooth functions in the interior of $\Omega$ and harmonic in $\Omega$. Suppose that $u,v \in C(\overline{\Omega})$ and $u \geq v$ in $\Omega$. Suppose that exists $x_0 \in \partial \Omega$ with $u(x_0) = v(x_0)$ and $|\nabla u| \leq 1$ in $\Omega$. (I took $1$ for convenience). Is the following inequality true?

$$ \limsup_{y \rightarrow x_0} |\nabla u (y)| \geq \limsup_{y \rightarrow x_0} |\nabla v (y)| $$

I dont know if is true, but if yes, it will help me to understand a passage of a paper. I tried to prove, but no success. Someone could give me a help?

thanks in advance!

This question is related to the last inequality of the case i) (and the case ii)) of lemma 2.3 of the article Existence of classical solutions to a free boundary problem for the p-Laplace operator, (I) by A. Henrot and H. Shahgholian

(the article is in the right side of the page)

1

There are 1 best solutions below

1
On

No, this is not true. Let $\Omega$ be unit disk in the plane, and let $u(x_1,x_2) = x_1$. Define $v$ on the boundary so that $v(x_1,x_2) = x_1 - M|x_2|$, where $M$ is large. Then $\partial v/\partial \theta$ is the harmonic function which takes large values on the boundary near $(1,0)$, approximately $\pm M$. Therefore, it will take on large values near $(1,0)$ inside the domain.