$$\int^3_1\dfrac1{x-1}dx$$ I use the integral union property to break the integral into a limit from $0$ to $1$ and $1$ to $3$ since $x$ cannot be integrated at $x=1$. Then, I solve both integrals and I'm left with $\infty-\infty$which is again indeterminate form... How do I resolve this?
2026-04-11 23:46:10.1775951170
Comparison Test for Improper integrals with result of indeterminate form
85 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in CALCULUS
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