Completeness property and computability

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I have this axiom which states the completeness property of a set $A$:

Suppose that $A$ is a set. Every non-empty bounded above subset of $A$ has a least upper bound.

But then my prof told me that this Completeness axiom causes computability issues (later on he talked about computable numbers -- so I have been thinking that he actually referred to that). The thing is, I don't really get what he means by that. What's the connection between that statement above with computability? Hope one of you can help? Cheers!

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The main link is related to failures of the completeness theorem if we read "real" as "computable real".

A Specker sequence is a bounded, increasing, computable sequence of rationals whose limit is not computable. If we view the sequence as a set of rationals, it is a decidable, bounded, nonempty set of rationals whose supremum is not computable.