$2x^2 - 6x - 5$
My workings are
$2 ( x^2 - 3x + (3/2)^2 - (3/2)^2 - 2.5 ) = 0$
$ 2 ( x - 1.5)^2 - 4.75 = 0$
$ (x-1.5)^2 = 2.375 $
From here I go on to find X which is not the correct answer .. Can anyone help me on where I have gone wrong ? Thanks in advance !
You divide by 2 twice. $ 2( (x-3/2)^2-4.75)=0 \rightarrow (x-3/2)^2=4.75$