Is there any function $ f$ analytic for $|z|<1$, such that
$f(1/2)=1/3$ and $f(\frac{1}{2n+1})=\frac{1}{2n+1}$ for $n=1, 2, 3, ...$?
I'm thinking analytic continuation, but I can't seem to get anywhere...
Is there any function $ f$ analytic for $|z|<1$, such that
$f(1/2)=1/3$ and $f(\frac{1}{2n+1})=\frac{1}{2n+1}$ for $n=1, 2, 3, ...$?
I'm thinking analytic continuation, but I can't seem to get anywhere...
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