Complex Limit with exponential

Question

I have no clue where to start with this. Any hints?

limit (as n goes to infinity) of $$e^{\frac{\pi((n^2+i)}{(in^2+1))}}$$

Answer 1

$\dfrac{n^2+i}{in^2+1}\to\dfrac1i$.

So we get $e^{-\pi i}=-1$, by continuity of $e^z$.