Express $(\sqrt{3} + i)^6$ in polar form.
Normally, it would be $2(cos(\pi/6) + i sin (\pi/6))$ but how about the 6? I don't know what to do with it.
2026-04-09 05:46:09.1775713569
Complex Number in Polar Form with 6th root
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Hint:
$(\sqrt{3}+i)^6= \left(2e^{i \frac{\pi}{6}}\right)^6$