Complex number : mth root of nth root

99 Views Asked by At

If one defines the $n^{th}$ root of a complex number ($n$ a natural number) so that it coincides with the usual one for the positive real :

  • its imaginary part is $\ge 0$
  • its real part is the largest among the $n^{th}$ roots whose imaginary part is non-negative.

Is it true that :

$$ \sqrt[m]{\sqrt[n]{x}} = \sqrt[mn]{x}$$