Complex Numbers: Solve for $z^8-z^4+1 = 0$.

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This is what I currently have. I'm not sure how to continue. Can someone show or teach me how it's done? A repost because there were flaws with formatting. Work:

\begin{array}{*{20}c} {x = \frac{{ 1 \pm \sqrt {1-4} }}{{2}}} \\ \end{array}

\begin{array}{*{20}c} {x = \frac{{ 1 \pm{i}\sqrt {-3} }}{{2}}} \\ \end{array}

$$z^4 ={r^4(\cos(4θ))(\sin(4θ)}$$