I have a permutation $ \alpha = (125)(1378)(12546)(126) $. I know that I have to follow this rule when calculating permutation in their cyclic form: Ex for the first term $$ 1 \rightarrow 2 \rightarrow 5\rightarrow 5 \rightarrow 1$$ So 1 goes to 1, which I can omit. Then the same rule applies for 2 and so on. When I calculate $\alpha$ like this I get this result: $\alpha = (2378)(465)$. Anyway I use this calculator to ensure that my result is right, which unfortunately it is not the case. The right answer is (15378624). So what am I doing wrong?
2026-04-02 11:23:51.1775129031
Composition of cyclic permutation
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