Computing $\int_{0}^{2π} f(re^{iθ}) dθ, r > 0.$

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Let $f :\Bbb C \to \Bbb C$ be an entire function.

Compute $\int_{0}^{2π} $$f$($re^{iθ}$) $dθ$, $r > 0$.

MY ATTEMPTS : From Cauchy's integral formula, $$ \lvert f^{(n)}(0) \rvert \le \frac{n!}{2 \pi r^n} \int_0^{2\pi} \lvert f(re^{i\theta}) \rvert \, d\theta $$
Now, I don't know how to to proceed further.

Please help me.

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Put $z=re^{i\theta}$.

Then $dz=izd\theta$.

Thus the integral becomes $\frac 1i \int_{\gamma} \frac {f(z)}{z} dz$ which is equal to $2 \pi f(0)$ by Cauchy integral formula where $\gamma$ is a circle $|z|=r$.