Conceptual argument for this combinatoric equation

39 Views Asked by At

$$\sum_{k=i}^{n} \binom{n}{k} \binom{k}{i} = \binom{n}{i} \cdot2^{n-i}$$

Can some provide a conceptual explanation of this (not an algebraic one)?

1

There are 1 best solutions below

0
On BEST ANSWER

Given an $n$-element set $A$, the LHS counts the ways of picking sets $B$ and $C$ with $A\supseteq B\supseteq C$ and $|C|=i$. What if you pick $C$ first, and then count how many $B$ are there with $A\supseteq B\supseteq C$?