Arrange
$$a,a,a,b,b,b,c,c,c,c$$
in a row such that there is at least one $b$ and one $c$ between any two $a$.
Arrange
$$a,a,a,b,b,b,c,c,c,c$$
in a row such that there is at least one $b$ and one $c$ between any two $a$.
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We have $3$ 'a's, and imagine 4 buckets between them.
$()a()a()a()$
We know a 'b' and 'c' must go in each of the middle buckets, ands we have 'bcc' left over.
$()a(bc)a(bc)a()$
There are $[xy^2]:\left((1+x)(1+y+y^2)\right)^4=40$ (WA) ways to disperse the 'bcc's.
Then multiply by the number of arrangements of each bucket for each of the $40$ placings.
Explicitly, the options for a '3-bucket' are:
$$(1+x+y+xy+yx+yy+xyy+yxy+yyx)\\=(1+x+y+2xy+3xy^2)$$
And for the two middle '5-buckets':
$$(2xy+3x^2y+3xy^2+6x^2y^2+4xy^3+10x^2y^3)$$
So:
$$[x^3y^4]:(1+x+y+2xy+3xy^2)^2(2xy+3x^2y+3xy^2+6x^2y^2+4xy^3+10x^2y^3)^2$$
=358 (WA)