congruence class

Question

Just wanted to know if I was on the right track with this answer.

([1] - [6]) * ([5] + [7]) 


LHS = 1 = 1(mod11)                          
    = 6 = 6(mod11)
    -5 = 6(mod11) 
    = [6]  



 RHS = 5 = 5(mod11) 
       = 7 = 7(mod11) 
       5 + 7 = 12 = 1(mod11) 
       = [1] 
   Final = [6] * [1] 

Answer 1

community wiki post so that the question can be closed

Yes, as stated in the comments, your approach is correct.