Consecutive Square Numbers divided by Consecutive Odd Numbers

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Why do we get this pattern (note what has been highlighted or italicized) when you divide consecutive square numbers with consecutive odd numbers ?

4 ÷ 3 = 1 R 1

9 ÷ 5 = 1 R 4

16 ÷ 7 = 2 R 2

25 ÷ 9 = 2 R 7

36 ÷ 11 = 3 R 3

49 ÷ 13 = 3 R 10

64 ÷ 15 = 4 R 4

81 ÷ 17 = 4 R 13

100 ÷ 19 = 5 R 5

121 ÷ 21 = 5 R 16

144 ÷ 23 = 6 R 6

169 ÷ 25 = 6 R 19

196 ÷ 27 = 7 R 7

225 ÷ 29 = 7 R 22

256 ÷ 31 = 8 R 8

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Your observation (in the bold) is that $(2n)^2$ divided by $4n-1$ has the result $n$ R $n$.

$(2n)^2=4n^2$ and if you multiply the divisor $(4n-1)$ by the quotient $n$ and add the remainder $n$ you get $((4n-1)\cdot n)+n=4n^2-n+n=4n^2$.

So that pattern is just what you expect.

Your observation (in italics) is that $(2n+1)^2$ divided by $4n+1$ has the result $n$ R $(3n+1)$.

$(2n+1)^2=4n^2+4n+1$ and if you multiply the divisor $(4n+1)$ by the quotient $n$ and add the remainder $3n+1$ you get $((4n+1)\cdot n)+3n+1=4n^2+n+3n+1=4n^2+4n+1$.

So that pattern is just what you expect.