A derivation is inner if it has the form $\text{ad}x$, $x\in L$. Otherwise, a derivation is outer. For a semisimple Lie algebra, every derivation is inner. What about the nilpotent and solvable cases?
2026-04-06 18:16:08.1775499368
Construct a outer derivation for every nonzero nilpotent/solvable Lie algebra
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Every nonzero nilpotent Lie algebra over an arbitrary field has an outer derivation. This was proved by Dixmier, and by Jacobson and Schenkmann in $1955$.
This is no longer true for solvable Lie algebras. Already the nonabelian $2$-dimensional Lie algebra $\mathfrak{r}_2(K)$ has only inner derivations.
Reference: Why, for nilpotent Lie Algebras, is the inclusion to the derivations $x \mapsto {ad}_x$ not surjective?
Yves has written down there the proof for nilpotent Lie algebras.
Note: It is not true, that all derivations of semisimple Lie algebras are inner. Consider the simple Lie algebra $L=\mathfrak{psl}_3(\Bbb F_3)$. Then we even have $\operatorname{Out}(L)\cong L$, see here.