Construction of continuous-time markov chain and finding stationary distribution

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There are 15 lily pads and 6 frogs. Each frog, with rate 1, jumps to one of the other 9 unoccupied pads chosen uniformly at random.
What is the stationary distribution for the set of occupied lily pads?

This is from Durrett's Essentials of Stochastic Processes.

I thought we would consider all possible combinations of occupied pads as states of a continuous-time Markov chain, so $15\choose6$ states. From there I suspect the stationary distribution is $\frac{1}{15\choose6}$ for every state. Is this a correct formulation? I am new to the subject of CTMC's so am not very sure in my answer.

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Yes, the states all have the same probabilities in the stationary distribution. This is easy to see once you notice that the process is reversible: given two states $s_1$ and $s_2$ such that a transition from $s_1$ to $s_2$ is possible (by moving one frog), the rate of jumps from $s_1$ to $s_2$ when in state $s_1$ is the same as the rate of jumps from $s_2$ to $s_1$ when in state $s_2$.