Contour Integral of $z \hspace{0.5mm} \exp(z^2)\,dz$

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Compute the integral $$\int_C z \hspace{0.5mm} \exp(z^2)\,dz$$ $C$ from $1$ along the axes to $i$.

So far Im having trouble parametrising the curve $C$. Any hints?

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Parametrization: $\gamma (t)=1-2t$ for $0 \leq t \leq \frac 1 2$ and $\gamma(t)=i(2t-1)$ for $\frac 1 2 \leq t \leq 1$.

Also, $ze^{z^{2}}=\frac 1 2 \frac d {dz} e^{z^{2}}$. Hence, the value of the integral is $\frac 1 2 e^{(i^{2})}-\frac 1 2 e^{(1^2)}=\frac 1 2(e^{-1}-e)$