Convergence of angle between vectors?

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This problem comes is from Hoffman's Analysis in Euclidean Space.


True or False. Let $\{X_n\}$ be a sequence in $\mathbb{R}^m$. If $\{X_{n}\}$ converges to a (nonzero) vector $X$, does the angle between the vectors $X_n$ and $X$ converge to $0$?

I am assuming it is true. Here is my attempt at a proof.


Proof. Assume that $\{X_{n}\}$ converges to the vector $X$. We know that $$\cos\theta=\frac{\langle X,X_n\rangle}{|X||X_n|}$$ for some positive integer $n$. Since $$\lim\limits_{n\rightarrow\infty}\frac{\langle X,X_n\rangle}{|X||X_n|} =\frac{|X|^2}{|X|^2}=1$$ then $$\theta=\cos^{-1}(1)=0$$


I can't see a reason why the converse statement wouldn't be necessarily true. In other words, if the angle between ${X_{n}}$ and some vector $X$ approaches zero, wouldn't the sequence $\{X_n\}$ converge to $X$?


EDIT: Another thing that popped into my mind. Do these results hold in general for all vector spaces?

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Your proof is correct.

The converse is not true because the angles do not speak to the norms. The angles may converge to a limit but the vectors do not have to converge due an oscillation in norms.