Evaluate the iterated integral $$\int_{-1}^1\int_0^{\sqrt{3+2y-y^2}}\cos\left(x^2+(y-1)^2\right)\,dy\,dx$$
Confused on how $y=0$ and $y=\sqrt{3+2y-y^2}$. Is this a typo or am I missing something?
2026-03-29 06:28:44.1774765724
Convert integration to polar and solve
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What are you confused about? As far as I can see the limits for the integral wrt $y,$ being $0$ and $\frac {1+\sqrt 7}{2}$ from the given conditions, are consistent with everything else.