Convert one equation into another form using Maple and see the steps

Question

I want to convert this equation exp(x - y)/(1 + exp(1)^(x - y))^2 into exp(1)^(x + y)/(exp(1)^x + exp(1)^y)^2 equation. And I want to see the steps to do that in maple. So far, I checked if both statements are equal using and it gave me a TRUE:

eq1 := exp(x - y)/(1 + exp(1)^(x - y))^2 = exp(1)^(x + y)/(exp(1)^x + exp(1)^y)^2;

is(eq1);

Answer 1

ee := exp(x - y)/(1 + exp(1)^(x - y))^2:

simplify(expand(ee));

      exp(x+y)/(exp(y)+exp(x))^2

Amongst several other ways,

combine(normal(expand(ee)));

      exp(x+y)/(exp(y)+exp(x))^2

Or were you looking for a more step-by-step approach, say in which a factor of exp(y)^2 were programmatically determined and used to adjust both numerator and denominator?