Converting A Riemann Sum into an Integral

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The expression given is:

$$\lim_{N\to\infty}\sum_{k=1}^N \frac{2M}{3N}*(\frac{2}{3} - (\frac{2}{3N})^k)$$

I was able to compute the limit and arrive at:

$$\frac{4M}{9}$$

Does this amount to integrating the function from 1 to infinity? If so how do I not integrate but extract the function? How do I know the function from this Riemann Sum?