I have a polynomial $f(z)=z^4+z^3-2z^2+2z+4$, and I want to find the number of roots in the first quadrant. I'm trying to use the argument principle (or Rouche), and I could try to make my contour the quarter circle, but I've having trouble because I can't justify that there are no roots on the real axis. Please give me some recommendations!
So now I understand why there are no roots on the contour; I have also justified that the integral on the arc goes to $2\pi i$ by normal limit considerations. However, I still am unsure how to figure out the arguments.
This one is a real weird one.
That is because I am tempted to factor this polynomial.
Let us try the rational root theorem first. If there is a rational root $\frac pq$ then $p$ divides $4$ and $q$ divides $1$ i.e. that root must be a multiple of $4$.
Merely trying out $z = -1$ works. Upon division by $z+1$ we get $z^3-2z+4$.
Another use of RRT gives $z = -2$ as a root, and division by $z+2$ yields $z^2-2z+2$, which by the usual quadratic formula is $(z-1+i)(z-1-i)$.
So, we have the roots as $1\pm i, -1,-2$. Of these, exactly the root $1+i$ is in the positive quadrant.
While this may be disappointing as an answer because we have not used machinery, it is suitable for a beginner. I would always suggest it as a first approach, and then look to apply Rouche or something else if things did not work out.