Creating a quadratic with specified gradient at point, and specified turning point y-value

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Simple question, though I can’t get my head around the rearrangement necessary when solving this with a system of simultaneous equations.

Specifically, I need to join a quadratic to another function together at a set point where the join is perfectly smooth and continuous, i.e. the gradient is the same at those points. I also need the quadratic turning point to hit a y-value of exactly 55.

Function 1: $0.1e^{x-5}$

Function 2: Quadratic with conditions

The join happens when Function 1 hits a y-value of 2.

There are three points of information, and three unknowns in a quadratic, so I know it can be done.