We know that cross product gives a vector that is orthogonal to other two vectors. Let this vector denoted by $$|\vec{v} \times \vec{u}| = \vec{n}$$ Then $$\vec{n}\cdot \vec{u} = 0 $$ Everything okay up to here. Then how we choose a vector from two possible orthogonal vectors, $$\vec{n}$$ or $$\vec{-n}$$ Why following right hand rule?
2026-03-28 03:35:02.1774668902
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cross product of vector and direction
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This is just a convention. We could use the opposite convention, and everything would work fine. However, the usual convention has the following nice property. For any two linearly independent vectors $u,v$, if we let $A$ denote the matrix whose columns are $u,v,u\times v$, then $\det A>0$.
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It is a matter of convention deriving from the convention on orientation of $x,y,z$ axis ( $ \vec i, \vec j, \vec k$) , so that
$\vec k= \vec i \times \vec j= \left |\begin{matrix} \vec i&\vec j&\vec k\\ 1&0&0\\0&1&0 \end{matrix} \right|$
I don't know why the right hand was chosen as positive, but i love to think that this has something to do with the spin of our Earth ( oriented counterclockwise).
There is no mathematical way to distinguish between the two directions, they are perfectly equivalent. But in the physical applications, there is a difference. Therefore by convention we use the right hand rule.
Why right and not left could be for any of the following reasons: