Everyone knows that a regular tetrahedron fits inside a cube, and that the volume of the tetrahedron is 1/3 that of the cube.
(For a picture, see this question or this Google image search.)
The question is, once you've cut the corners off the cube to make that tetrahedron, what's a simple way to cut up those four corner pieces so that their parts can be rearranged to form two additional regular tetrahedra?
You can't do it.
This is because of Hilbert's third problem: https://en.wikipedia.org/wiki/Hilbert%27s_third_problem
(At least, I think this is true.)