D-Product (Absolute U AND V)

Question

Can someone explain for solution b why absolute u is 2 and absolute v is 1. I am a little confused with d-product examples.

Answer 1

for part (b), you have $\vec{u} = \left(\sqrt3,1\right)$ and $\vec{v} = (0,1)$. You have $$ \left\| \vec{u} \right\|^2 = \vec{u} \cdot \vec{u} = \left(\sqrt3\right)^2 + 1^2 = 4 $$ which means $\left\| \vec{u} \right\| = \sqrt{4} = 2$.

Can you do the other one yourself?