Deceleration of an aircraft while braking.

Question

I'm trying to determine the distance an aircraft traveled during a period of brake application using the following information:

Initial speed (v0) = 92 nautical miles per hour, Final speed (v1) = 67 nautical miles per hour, Initial time (t0) = 0, Total braking duration (t1) = 5 seconds, 1 NM = 6067.12 Ft,

So I get that the aircraft slows at 25 nautical miles per hour in 5 seconds, but how do I get to how far in feet it traveled in that slice of time?

Answer 1

I will assume constant acceleration $a = - 5$ NM per hour per second.

first convert $v_0$ into units of feet per second and $a$ into units of feet per second squared.

then you can get the distance travelled from the formula ...

$$d = v_0 t + \frac 12 a t^2 $$

don't forget that $v_0 > 0 $ and $a <0$ and $t=5$s