Decomposition of SU(n) anticommutator

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In $SU(N)$, the special unitary group, the algebra generators $T_a$ are hermitian and traceless. The structure constants are fixed with $[T_a,T_b]=i f_{abc}T_c$. In the fundamental representation of the group ($N\times N$ matrices) the anticommutator can be decomposed, being an hermitian operator, into its trace part and traceless part: $$\{T_a,T_b\}=C_{ab}\mathbf{1}+d_{abc}T_c$$ with $C_{ab},d_{abc}$ two tensors. Does this relation holds for every representation of the group?