deduce that there exists a unique polynomial q(x) of degree at most n such that$ q(c_i)=a_i$ for $0 \leq i \leq n$.

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Let $V=P_n(F)$ (the vector space of polynomials with coeffficients in R of degree at most n), and let $c_0,c_1,...,c_n$ be distinct scalars in F. For any scalars $a_1,...,a_n$, deduce that there exists a unique polynomial q(x) of degree at most n such that$ q(c_i)=a_i$ for $0 \leq i \leq n$. In fact $q(x)=\sum_{i=1}^n a_i p_i(x)$.

The hint says for uniqueness, prove that ${p_0(x),p_1(x),...,p_n(x)}$ is a basis for $V=P_n(F)$. My question is how to prove the existence? And after that we need to use the hint right?

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The same problem gave you the recipe of how to construct the desired polynomial, just put $$q(x) = \sum_{j=0}^n a_jp_j(x)$$ and we check that this satisfy $q(c_i) = a_i$. But this is easy, since $$q(c_i) = \sum_{j=0}^n a_jp_j(c_i) = \sum_{j=0}^n a_j \delta_{ij} = a_i.$$